S
Sunil
- Jan 1, 1970
- 0
hi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
and how do you find it out experimentally??
Sunil said:hi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
my professor measured it using the ratio between Rin and Rs (internal
resistance)....i kinda dint understand that...can u xplain me this
method??
Sunil said:my professor measured it using the ratio between Rin and Rs (internal
resistance)....i kinda dint understand that...can u xplain me this
method??
Rich said:Why can't you go to the prof., and say, "I still don't get this -
can you explain it to me again, in a form I can understand?"
Connect a battery and a resistor in series with a base emitter junction.hi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
bg said:Sunil wrote in message
Connect a battery and a resistor in series with a base emitter junction.
Measure the voltage across the resistor and the voltage across the BE
junction. From ohms law you can figure out the current flowing into the
junction and the resistance of the junction.
Ok so we measured h and not Bh, but the flaunting is not negotiable.Eeyore wrote in message said:You just measured a DIODE not a transistor.
Please don't flaunt your ignorance in this way.
Graham
Now you're starting to sound like one of the brothers,Eeyore said:Sunil wrote:
It depends on the circuit it's operated in. If you're referring to the device
itself alone, those parameters will vary with collector current.
By measurement !
Now, maybe you can us about the reason behind your question.
Graham
No comment.. How ever, I do admire your truthfulness.Eeyore said:Rich Grise wrote:
I went to the Prof (age 18) and said (something along the lines of to the best
of my memory) why are you using Y parameters when no damn * (OK I didn't say
"damn") semiconductor manufacturer publishes any such damn * thing and I think
he was mostly embarassed that a student was probably better informed about
current practice than he was.
His answer when I suggested that H parameters might be more useful was IIRC
"that's another way you can do it". DUH !
What a useless piece of trash ! I had 2 very good friends on the course who both
admitted at the end of the first year "I still don't understand what a
transistor does". I did and I hadn't learnt it at UCL and that's why I left.
Graham
Pay no mind to Mr Ham.. He can be as rude as he can be ignorant.bg said:Ok so we measured h and not Bh, but the flaunting is not negotiable.
thanks
Jamie said:Pay no mind to Mr Ham.. He can be as rude as he can be ignorant.
Jamie said:Now you're starting to sound like one of the brothers,
here in the states!.
Keep it up, you'll be wearing an American patch very soon!
The book, "The Art of Electronics" does an excellent job of explainingSunil said:hi.....can anyone define input and output impedence of a transistor??
and how do you find it out experimentally??
Graham is right. I gave a wrong answere.Unlike some people, I don't have aPay no mind to Mr Ham.. He can be as rude as he can be ignorant.
Frankly, I don't understand the instructor placing a question in suck
an awkward manner? In any case. Your idea of applying current in the base,
assuming the emitter is at common, is just one step less than that of
the final process of measuring the current from source to C.(collector).
This would then give you the current gain ratio. found in reference of
Hfe, also found in text as Beta.
Now most of us know, that figure is not absolute due to the nature of
bipolar transistors.
The above assumes bipolar, since, that is most likely what they teach
first in school.
bg said:Jamie wrote in message ...
Graham is right. I gave a wrong answere.Unlike some people, I don't have a
problem with that.
bg
Eeyore said:Jamie wrote:
"Brothers" ? I thought that was a reference to 'black' people.
You change your mind like most people change their underwear.Not everything American is a bad thing !
Graham
I understand that how ever, the procedure you describe even thoughbg said:Jamie wrote in message ...
Graham is right. I gave a wrong answere.Unlike some people, I don't have a
problem with that.
bg
That's today.Eeyore said:bg wrote:
I apologise for my bluntness.
Graham