- Joined
- Dec 18, 2013
- Messages
- 5,178
It's a bit small I can't make it out. First have ago at the Thevenins question first. I'll work on the Norton's for you. But as this is homework I can't give you the answer.
Adam
Adam
Ohm's Law relates 3 items: voltage, current, resistance. Given any two the third can be calculated....if I could work out the resistance then the rest will follow?
Adam its not homework its extra work i'm doing to try and improve my understanding ready for when I start college next march. I asked the tutor for some extra circuits but not this hard.
Post #26 dealt with the image file from post #20, which was a different problem.I think you realize that the topology of the schemat in post #26 is not correct. R6 is missing. I also think the best way to solve this problem is to convert the delta resistor configuration of R2,R3, and R6 into a Y configuration.
Looking for the total current flowing through a bridge. Attached image shows the node equations for the two bridge voltages. Total current into the bridge is Ii=(1-Vab)/Ra+(1-Vcd)/Rc where Vi has been arbitrarily set to 1 for convenience. Equivalent resistance is Req=Vi/Ii.
View attachment 17718
Interesting, indeed. And done in 1947 before the advent of modern mathematical computational tools that can give the same results in just minutes of interaction with the PC. I wonder how many reams of paper the author used to derive those simplifications? The year 1947 seems like just a short time before I first learned algebra.You might find it interesting to have a look at this: