D
Dave
- Jan 1, 1970
- 0
Hi all -
I've got a 2N5462 device that I'm trying to set up as a basic high-side
switch. I just want to turn on an LED to show the basic circuit connection
and have the MOSFET swtich it on and off with a toggle switch on the gate.
I connected the source to a +5VDC source, the gate through a 100-ohm
resistor to ground, the drain to a resistor connected to an LED to ground.
I put a toggle switch with a series 10K resistor from the +5VDC line to the
gate.
When I turn on the circuit power, the LED lights up without the toggle
switch pushed. I looked at the voltage on the gate and its sitting at
around 3.5VDC. Without the switch pushed, the gate should be pulled low
through the 100-ohm resistor. Why is it this high? Do I have this
connected incorrectly? Is the 2N5462 device actually an P-channel MOSFET
(as described in one datasheet) or a JFET amplifier (as described in another
datasheet)?
Any help would be appreciated.
Thanks.
Dave
I've got a 2N5462 device that I'm trying to set up as a basic high-side
switch. I just want to turn on an LED to show the basic circuit connection
and have the MOSFET swtich it on and off with a toggle switch on the gate.
I connected the source to a +5VDC source, the gate through a 100-ohm
resistor to ground, the drain to a resistor connected to an LED to ground.
I put a toggle switch with a series 10K resistor from the +5VDC line to the
gate.
When I turn on the circuit power, the LED lights up without the toggle
switch pushed. I looked at the voltage on the gate and its sitting at
around 3.5VDC. Without the switch pushed, the gate should be pulled low
through the 100-ohm resistor. Why is it this high? Do I have this
connected incorrectly? Is the 2N5462 device actually an P-channel MOSFET
(as described in one datasheet) or a JFET amplifier (as described in another
datasheet)?
Any help would be appreciated.
Thanks.
Dave