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Inverting op amp feedback parameter B

Harald Kapp

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Buenos dias, Ignacio.

I refer to equation 1.7 in your reference and the following paragraph where it states."The feedback parameter β depends only on the characteristics of the feedback network." This means, different feedback networks have different values for β.

When you scroll a bit further you'll find on page 10 that β = R1/R2 for the inverting circuit.
Equation 1.19 on page 15 states G = 1+R1/R2
which is equivalent to G = R2/(R1+R2) and thus β = (R1+R2)/R2

You see: different circuit topologies, different equations (values) for B.

Saludos,
Harald
 

LvW

Apr 12, 2014
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Harald - I have some problems with your contribution.

* β = R1/R2 is NOT correct.

* β = (R1+R2)/R2 can also not be correct because a passive feedback factor can never be >1.

Ignacio: The expression for the feedback factor on page 10 is wrong!
In both cases - inverting and non-inverting amplifier - we have the same feedback factor β = R1/(R1+R2)
 
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Harald Kapp

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I don't like it but I have to confess that I was wrong. The document cited mixes feedback factor and gain.
 

LvW

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Yes - and these explanations can also be found in each relevant text book.
Therefore, my recommendation: Before asking similar questions consult a serious textbook and do not blindly rely upon any internet-sources.
 

IgnacioSS

Jul 10, 2018
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Thank you very much for your recommendation.

I'm an amateur who has started studying on his own by reading "The Art of Electronics".
As this book does not usually develop the concepts mathematically, and I like to know where the formulas come from, I try to find it on the internet.
But maybe that book is not the best for me. Maybe you can recommend me a better one.
 

LvW

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G seems to be something call "input damping factor": https://electronics.stackexchange.c...inbeta-derivation-for-the-inverting-amplifier
At the end of the day, Acl is just the superposition of the G (Rf/(Ri+Rf)) and B (Ri/(Ri+Rf)) factors:
V- = Vout B
V- = Vin G

Yes - it is common practice to apply the general feedback model as shown in your post#6.
Here, the input signal Vn that arrives directly at the inverting (minus) input node of the active device (opamp) , consists of two parts (superposition): Vn=Vn1+Vn2.
One part is derived from the output called beta: Vn1=beta*Vout (assuming Vin=0)
The other part is derived from the signal input: Vn2=G*Vin (assuming Vout=0)
Note that for non-inverting opamp applications, we have G=1.
Together with the given feedback formula for the closed loop gain Acl and assuming Aol infinite, we arrive at the expression for the closed-loop gain Acl=-G/beta.
Alternatively, with infinite Aol we can set Vn=0 (Vn1=-Vn2) from the beginning and immediately arrive at the same expression.

My favorite book is Sergio Franco: "Design with Operational Amplifiers."
However, there are many similar books on the market - some of the are also availbale via internet (for example Roberge: "Operational Amplifiers").
 
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