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Convert watts to Teslas?

J

John Larkin

Jan 1, 1970
0
I realize this depends somewhat on emitter coil efficiency ... but
given an air core solenoid and sinusoidal audio frequency signal, is
there anyway to approximate how many microTeslas I will get per mW?

Much thanks,

Lester


No. You have to know the coil current and the geometry, and do the
math.

John
 
L

Lester Crane

Jan 1, 1970
0
I realize this depends somewhat on emitter coil efficiency ... but
given an air core solenoid and sinusoidal audio frequency signal, is
there anyway to approximate how many microTeslas I will get per mW?

Much thanks,

Lester
 
T

Tim Williams

Jan 1, 1970
0
None, inductance is lossless. <BG>

You might have luck with VAr or volts however...

Tim
 
R

Robert Baer

Jan 1, 1970
0
Lester said:
I realize this depends somewhat on emitter coil efficiency ... but
given an air core solenoid and sinusoidal audio frequency signal, is
there anyway to approximate how many microTeslas I will get per mW?

Much thanks,

Lester
NO!
Measure it; the magnetic field will vary with the signal / drive.
 
J

John Woodgate

Jan 1, 1970
0
I read in sci.electronics.design that Lester Crane <[email protected]>
wrote (in said:
I realize this depends somewhat on emitter coil efficiency ... but
given an air core solenoid and sinusoidal audio frequency signal, is
there anyway to approximate how many microTeslas I will get per mW?

No, because the field strength varies wildly with where you measure it.

In any case, you don't need ANY watts to produce the field (except for a
very short time during which the field is set up). Power dissipated in
the coil is just I^2R, and you can get the same field from any value of
R from zero (superconducting coil) to large (thin wire, many volts
required to produce the required current).

If you say what you are actually trying to do, I may well be able to
help. This is an area in which I do a lot of work.
 
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