Connect with us

Common Emitter Gain question

Discussion in 'Electrical Engineering' started by H. Neary., Nov 19, 2004.

Scroll to continue with content
  1. H. Neary.

    H. Neary. Guest

    Work out Xc, then work out the gain using Xc in parallel with Re.

    HTH

    HN
     
  2. Peter

    Peter Guest

    I have a circuit that I understand the DC gain, but I don't understand the
    AC gain.

    the top resistor on the base from Vcc is 18k, bottom is 18.2k into a 2n3904
    with an Re of 562 and an Re of 1k, vcc is 9v.

    There is a cap in parallel with Re that is 100uf and my input freq. is 1kHz.

    The DC gain should be Rc/Re which is a little less than 2. But when I scope
    the input and the output, it's like 100 times.

    I understand that cap is bypassing all the AC to ground, but why the higher
    gain?
     
  3. Peter

    Peter Guest

    I tried that and my gain is like 629 when my gain is clearly 100 because I'm
    looking at the input which is 1mV rms and my output is approx. 100mV rms.
     
  4. H. Neary.

    H. Neary. Guest

    Sorry, it was obviously more complex than my simplistic approach. I'll
    dig out my old text books if no-One provides an answer. I know that ac
    gain in common emitters was something that was done to death on a few
    of my courses in analogue electronics. Strange really, I seem to have
    spent the whole of my career without having needed the theory once :)

    HN
     
  5. TimPerry

    TimPerry Guest

    http://hyperphysics.phy-astr.gsu.edu/hbase/electronic/npncegain.html

    http://www.ecircuitcenter.com/Circuits/trce/trce.htm

    take a look at these sites.

    do you have a load resistance? if so it parallels Rc

    dont forget about the resistance in the emitter junction (r ej). its small
    but adds in series to the ac resistance.
     
  6. bushbadee

    bushbadee Guest

    Maximum common emmiter gain is 40 X Vcc

    That occurs near saturation.
     
  7. Peter

    Peter Guest

    I don't think it's 40 x Vcc

    I think what I was missing was that I needed to include re' in the equation
    too and also consider the resistors on the base of the transistor (r1 and
    r2)
     
  8. bushbadee

    bushbadee Guest

    re depends on the current flowing'
    At 1 Ma it is about 25 ohms.
    The value of 40 Vcc is for a grounded emmitter configureation
    Close to saturation the current is limited by Rc.
    This means that as Rc gets bigger the current drops and re also gets bigger
    in proportion to Rc.
    Because they track, both drop out of the equation and the gain is 40Vcc.
    If there is a substantial externam emmitter resistance which is a lot bigger
    than re than the gain is Rc over Re.
    If Re is not a lot bigger than re then the effects of re must be considered,
    but remember re is a moving target varying with current. and the gain varies
    with the current flowing.
     
Ask a Question
Want to reply to this thread or ask your own question?
You'll need to choose a username for the site, which only take a couple of moments (here). After that, you can post your question and our members will help you out.
Electronics Point Logo
Continue to site
Quote of the day

-