Very early morning to you all! I'm currently studying basic electronics and the theory behind it all and such and I took a 3 month class earlier last year that covered it all pretty much however it's been a long time since I've used that knowledge and have gotton a bit rusty on the mechanics of it. below is a simple common-base amplifier circuit that I found in a book and my question is,
The book states that the voltage being applied to the Emitter is negative because of the voltage drop across R2. What I'm having trouble understanding is why that voltage is negative even though there's what appears to be an AC input connected directly to the emitter? and how does R2 effect the emitter if it's supposed to take the path of least resistance?
I already get how transistors work with regards to the biasy and how the emitter has to be more negative than the base, what I am confused on is how this circuit makes that happen.
Sorry if my question is confusing, for me learning how it all works makes understanding it alot easier so any help would be appreciated!
http://oi50.tinypic.com/14wvwk.jpg <- the circuit mentioned
The book states that the voltage being applied to the Emitter is negative because of the voltage drop across R2. What I'm having trouble understanding is why that voltage is negative even though there's what appears to be an AC input connected directly to the emitter? and how does R2 effect the emitter if it's supposed to take the path of least resistance?
I already get how transistors work with regards to the biasy and how the emitter has to be more negative than the base, what I am confused on is how this circuit makes that happen.
Sorry if my question is confusing, for me learning how it all works makes understanding it alot easier so any help would be appreciated!
http://oi50.tinypic.com/14wvwk.jpg <- the circuit mentioned