Keep looking, it may be fine.
Purely synchronous machines only work when they're already spinning at
close to synchronous speed. So real-world synchronous machines have some
scheme to start them up (usually as an inductive machine), then a way to
switch them to being synchronous. Often the rotor will be shorted during
startup, then driven with a DC current for synchronous operation. This
_may_ happen with a centrifugal switch inside the motor. If so, the DC
current wire would appear as an open circuit until the motor is up to
speed.
Thread also here:
http://www.vintage-radio.net/forum/showthread.php?t=65010
Lets just look at what the overall situation is:
This is the machine:
http://www.vintage-radio.net/forum/attachment.php?attachmentid=46003&d=1296589576
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In order that the paper is taken from the spool containing the blank
chart paper, the shaft on the paper feed gearing assembly must rotate CW
(looking from the assembly's shaft end, that is looking RIGHT). If you
bolt a motor onto this gearing assembly it would therefore would need to
be a CCW motor looking at the motor from the spindle end (assuming one
spindle).
..............LEFT..........................RIGHT
---M1>-----Clutch-----<M2>----<SHAFT (CW)
M1 is a 240V self-starting synchronous motor at 25RPM. I presume it's a
50Hz motor. It's direction (looking from it's spindle end) is CW. The
clutch transmits this torque through to M2 (M2's spindle goes right
through the motor, M2 therefore has two spindle ends, to it's left M1,
to it's right the SHAFT).
The clutch does not transmit torque if the spindle from where the torque
is coming from is not in the required direction of rotation.
If M1 was connected via the clutch then directly to the SHAFT (no M2),
the mechanism would actually fail to take up paper from the paper spool.
It would try to feed paper to it.
When M1 is running, if I hold the end of the clutch I can cause M1 to
momentarily reverse, but corrects itself and resumes it's start-up
direction (CW).
But of course, we have M2 in between the clutch and the SHAFT. It
appears then M2 must rotate in a direction opposite to M1, in order that
paper is taken from the spool. In other words, if I position myself to
the right of M2, the shaft of M2 must rotate CCW.
The speed of rotation of the SHAFT can be set by a SPST switch as HIGH
or LOW. The speed difference is a factor of 60. The paper feed rate goes
from so many inches per second to per minute.
At the moment I still feel M2 is a motor.
Remember: About a 50 year-old chart recorder paper feed arrangement. How
does it work?
Here is the circuit if I have made no mistakes. I'm making assumptions
about the coils in M2, but there are 4 wires to M2:
http://www.vintage-radio.net/forum/attachment.php?attachmentid=46264&d=1296998790
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Okay, Here we have a situation where the change in SHAFT speed has to
be a factor of 60. SHAFT speed needs to be (I've reckoned) 16.67 RPM
when it's so many inches per minute and 1000 RPM when it's so many per
second.
M1 is a GEARED self starting 240V AC 50Hz synchronous motor. It's speed
is 25 RPM. It's direction is opposite to what SHAFT rotation should be.
M2 is NOT a geared motor and takes same AC mains as M1, which must be
240V 50Hz. Is it likely that M2 will run as a motor at the required
16.67 RPM? I'd say no at 50Hz, but am no expert. It seems a 12 pole
motor. It might run at 1000RPM.
M1 and M2 connected by a clutch that transmits torque, but only if
rotation is correct direction.
If M1's speed was 16.67 RPM and rotating in the proper direction, and M2
was a motor with speed of 1000 RPM, and either (but not both) M1 or M2
was in operation, the problem would be solved. But, this is not
apparently the case. At best M1 is always in operation and M2 is
energised preumably only on high speed.
Working of the machine is not easy to fathom. Needs the manual or
someone familiar with 1950's chart recorder technology.