Archimedes said:
Hi all
What would happen if you connect 2 resistors together in series and
then connected a capacitor also in series (say to the end of the 2nd
resistor). What will happen to the voltage divider? This is a DC
circuit.
Regards.
Specifically?
Well, If you have R1, R2, C, I and V then
Q = C*Vc, I = dQ/dt, and we'll write R1 + R2 as R
the loop is
V - I*R - Q/C = 0
or
V - R*dQ/dt - Q/C = 0
You'll notice that the current doesn't care if you are dividing the
voltage(assuming the load is very large when you do this).
So your equestion reduces just to one resistor and capacitor
The solution is I = Q0/R/C*exp(-t/R/C)
Where Q0 is the initial charge. here we are assuming the capacitor is
charging and that Q0/C < V.
Obviously now that you know the current you can find the voltages on the
resistors. Ofcourse all this work is unecessary because the current will
stop flowing(approximately) after a while and the voltage drop across the
resistors will be 0. Ofcourse if you need to analyze the transients then the
above is what you want.