W. eWatson said:
I bought a Light Keeper Pro at an ACE h/w store yesterday. It isolated
the problem to the first four bulbs in the string that was out. My
problem may now be finding four bulbs. I guess I can cut them out of the
string and solder things back together.
You could, but that would cause other bulbs in the remaining string
of 46 to burn out prematurely. Also with a 3 wire string, you need
to be able to figure out where to connect the wire (or the resistance
described below to bypass the open bulbs. With some of the strings
I've seen, the twisted wires make that too damn hard in my opinion.
Regarding premature burnout and resistors to replace the bulbs:
Each bulb in the original string of 50 drops a certain amount of
voltage. If the original string contains only bulbs and wires, then
each bulb drops ~ 2.4 volts (120/50). With 4 bulbs gone, you want to
find another way to drop ~9.6 (4*2.4) volts. Otherwise, the 46 bulbs
are each subjected to voltage a bit higher than normal, and will
burn out more quickly.
Probably easiest to buy another string, but if you want to proceed
and use a resistance to drop the voltage, you'll need to measure the
current drawn by a fully operational string. That will be I in the
formula E = IR. Solving for R: R = E/I. E is the voltage drop,
assumed to be 9.6 volts. It would be better to measure the voltage
drop across 4 bulbs in the fully operational string, and use that
measurement for E in the formula. R is the resistance required to
drop E volts at I current. The wattage dissipated would be I^2*R and
the resistor(s) would need to be rated at least twice that for a
safety factor. Since the resistance might touch flammable material,
you probably want a lot higher rating. More on that follows.
I don't know the specifics of your string, so I'll make up a value
for I: 200 mA. Using 200 mA and 9.6 volts, the required resistance
would be 9.6/.2 or 48 ohms, and the power dissipated would be 1.92
watts. I'd use 5 ten ohm, one watt resistors in series. That way
the dissipation would be spread across 5 resistors which would keep
the temperature lower. Whatever the actual number turn out to be,
you want to spread the heat out over a large enough area to keep
the temperature well within safe limits.
Replacing the bad bulbs with identical new bulbs, or replacing
the string, avoids all of that.
Ed