Sir Wilson2308 . . . . .
Seeing the hard grey ceramikote conformal coating and a sloping spiral hump underneath it.I lean towards it being a wirewound resistor.
That being , instead of its other alternative of it being a metal film resistor.
A STRONG neobdmium magnet placed at its mid point might confirm a central powdered iron / ferrite core such as a wound inductor might have.
But ignore any attraction to its leads, as most metal amalgams are altered so as to be semi magnetic for machine handling at board robo stuffing operations.
1...Give us brand and model of the unit remove from, since positive Identification might be as close as its bill of materiel listings of its schematic.
2... Measure across the resistor leads with an ohmmeter, expecting a low or very low value . .ergo . . expecting it to be good.
3...If it reads open . . . .somehow,seems like it has not had enough overload across it to open circuit . .viewing its insulative conformal overcoating OR the probable peak power current capacity of the power supply associated with it.
Place a wire jumper, that shorts both ends of the resistor together.
Now take Ohmmeter in its lowest range and one of its leads connects to the now co-joined resistor leads and the other lead goes to either a metal single edged razor blade or a metal Exacto knife blade.
The meter lead is index finger /to /thumb clamped into contact to the blade . The blade is then pivoted over to the paired resistor leads to take an ohms resistance . . .it being mentally noted.
Then the very center of the resistor is scraped at a hump until the insulative coating opens and an ohms reading pops up.
Take that reading and subtract the earlier combined lead resistance presence, and double that resistance, and you should be very close to the original resistance of the unit.
73's de Edd