I would like to connect linear temp. probe to one of the 8 bit A/D convertor of my PIC mcu.
Below is the schematics I found on the internet.
Equation for the voltage divider Vout=Vin*R2/R1+R2.
So if I take te specifications for common 100pt linear thermistor:
1kohm at 0°C
0.385ohm/K
max voltage 9V
max current 2mA (1mA suggested)
I need 4kohm R2 to limit the current to 1mA. So if I put those data to the upper equation I get Vout at 0°C to be 1V and at 100°C also rounnd 1V.
If I change R1 and R2 (thermistor up) I get Vout at 0°C to be 4V and at 100°C also round 4V.
So how can I get that output voltage will be between 0 and 5V?
Below is the schematics I found on the internet.
Equation for the voltage divider Vout=Vin*R2/R1+R2.
So if I take te specifications for common 100pt linear thermistor:
1kohm at 0°C
0.385ohm/K
max voltage 9V
max current 2mA (1mA suggested)
I need 4kohm R2 to limit the current to 1mA. So if I put those data to the upper equation I get Vout at 0°C to be 1V and at 100°C also rounnd 1V.
If I change R1 and R2 (thermistor up) I get Vout at 0°C to be 4V and at 100°C also round 4V.
So how can I get that output voltage will be between 0 and 5V?
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