Hello all...new to your forum...thanks in advance. Took/forgot physics, so I have a vague idea of AC/DC theory, but not its particulars/many caveats. I am working on a welding project and need some advice on some fairly high current switching of AC to DC. I am taking an AC arc (old fashioned "stick") welder, and converting it's output to DC. There are many reasons to do this...it boils down to being a smoother weld with more versatility too, with reversal of it's terminal polarity used for varying metals/thicknesses. It is supposed to put out 90 amps continuous, I am told RMS, at about 38 volts. I'm also informed that I ought calculate for peaks of double that 90 amp current. A bridge or 4 diodes at this high amperage gets expensive quick. My questions are these: 1) Anyone aware of a reason I could not wire two of these... http://www.sanrex.com/images/PDFs/BKR400AB10.pdf ...up, back to back, to form your classic, 200 amp bridge? There's a schematic lower on that page. They are $13 each online as opposed to other solutions at >$120. 2) Is being "shottky" a problem or advantage here? 3) From what I remember, a higher component voltage rating like this (100v rated component; 38 volts actually running) is not the problem that a too low current rating would be in practicality, correct?? Any input appreciated!
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