S
Simon S Aysdie
- Jan 1, 1970
- 0
I measure the Q of a 105nH inductor at 50Mhz my equipment max.
The Q is 80.
This is 57 / 80 = .71 ohms
But I'm using the inductor at 100Mhz.
Is there a way to calculate the Q at the higher frequency?
Yes, and you should listen to R. Macy.
Q as a function of frequency:
Q(w) = w*L/(R_DC + ((w_0*L/Q_0) - R_DC)*sqrt(w/w_0))
w = 2*pi*f
R-DC := DC resistance
Subscript "_0" means the frequency at which you know the Q.
The presumption is that you are operating below any frequency where the self resonating capacitor has substantive effect. That is, you are in the "sweet range" of an air core inductor.
Q = w*L/R_total
Generally,
R_total = R_DC + R_skin + R_core + R_dielectric + R_radiate
For what I gave you, it is only R_DC & R_skin (R_dielectric lumped in)
Generally too, *everything* is a function of frequency except R_DC, by definition. So the formula, again, is bounded to the "sweet range" of an air core inductor.