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Adding accessories to component systems

tedstruk

Jan 7, 2012
476
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Jan 7, 2012
Messages
476
motorcycle accessories are all the rave....
so here is my final workup on the overpower tail light problem I have created for myself...

Alternator puts out 14v 20amps @ 5000rpm to charge a 12v/20ah battery

if I run an accessory of 5 - 27.5w bulbs, which totals to 137.5watts
My alternator puts out 280watts at 5000 rpm....
but I have a 4 amp regulator, which reduces the power capability substantially--
280w / 4a = 70v which is about 68v short of what I need.
assuming this same equasion with the actual watts instead of alternator watts at 5000rpm
137.5w / 4a = 34.375v still way too high.

inventory-
60w headlamp
8w x2 = 16w tail
27w x2 = 64w brakes (intermittent mostly off)
27w x 4 = 108w signals(intermittent mostly off, 64w normal max flash)
3.8 x2 = 72w plate light
control board
3.4w x9 = 30.6w indicators
8w x2 =16w running lights
366.6w total standard wattage
137.5w of accessories
504.1w required

a 20ah, 12v battery delivers 240watts.
504.1w required - 240w available = 264.1w
because 264.1w is larger than 240w
we could say we have a 504.1w drain of 24.1w
We can't build a speciallized 504.1w system, because we are using 24.1w too many...
because the system has intermittent usage of the turn signals and the brake lights and the control board,
the system is working ok.... but it can't deliver the 4a that is nessesary to charge the battery
24.1w / 12v = 2amps
So if I can create a direct input generator that delivers 2amps into my fancy accesory it should allow the regulator to charge the battery... as it is, the regulator is taxed 2amps by the accessory, leaving only 2amps of charging power to charge the battery...
THE BATTERY SULFATED AND DIED!

so I would need to isolate the original system, make a secondary set of controls-add a battery-and generate 137.5w @12v
and the 11.46a that this produces could trickle spare charging power in, if needed. Like 20ma for 16hrs with a drain shunt to the main battery when the engine is off. caveat- the battery that I add will have to be larger than the one the system already has in it.
Whoo whoo was that a train?
 

Bluejets

Oct 5, 2014
6,926
Joined
Oct 5, 2014
Messages
6,926
Loads in automotive run in parallel. Your assumptions and calculations are incorrect to arrive at a final outcome.
 

tedstruk

Jan 7, 2012
476
Joined
Jan 7, 2012
Messages
476
reprisal by rote...
When you generate current, you are creating more problems. more resistance, more amperage, more more more..
this problem is a real pain because it jumps back and forth between more and less, and I guess that's the only way to do it right.
But all I really need is that extra 11.46 amps, and to me that is do-able....
Amplifiers increase current and in my mind an 11.46 amplifier is better than a battery,regulator rectifier and gobos lights all around....
So what if I tapped into the AC generator before it goes into the rectifier regulator, and just add what I need to power the accessory?
 

duke37

Jan 9, 2011
5,364
Joined
Jan 9, 2011
Messages
5,364
A 20Ah battery does not deliver 240W, it will deliver what the load needs within reason. A car starter motor takes about 3000W for a few seconds with a battery not much bigger than yours.

Add up the current of all the devices. Compare this to the 20A alternator. You will see if there is a lot spare.
The high voltages you calculate are rubbish, they do not occur. Everything runs on 12 to 14V.

Taking three phase AC direct from the alternator windings will not help and will add complications.
The 20A alternator is rated at 5000rpm, it will give less current at lower speed.

I do not understand why there is a 4A regulator to control 20A.

What is a gobos light?
 
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