I’m trying to understand how the component values are chosen for a battery eliminator circuit by reverse engineering.
Original Design:
Vs supply +140 V
(6) 22V 5 watt Zeners In series
(5) 1N2007, (.7 X 5 +3.5V) forward biased in series
(1) 300 ohm 3 watt resistor (Rs) in series
A 70 mA load at 135V tap.
I calculated :
max Iz = 5 watt/ 22 volts = .227A - .07A (load)
Rs(min) = (Vs- Vz)/(Iz-I load = (140 – 135)/(.227- .070) = 35 / .157 = 223 ohms
Rs (wattage) = P = I (sqr) x R = (.227 X .227) X 223 = (.025) X 223 = 5.5 watts
Is there an error in my calculation?
Obviously they used a higher value Rs which lowered the wattage required. My question is how did they pick the value of 300 ohms.
Is there a rule of thumb when selecting Rs, as opposed to using the minimum value and adding resistance, trial and error, to get a reasonable wattage?
If I increase Vs (Supply) to +200V, this will also increase my wattage rating of components. Should I add more Rs resistance, or add more zeners?
Original Design:
Vs supply +140 V
(6) 22V 5 watt Zeners In series
(5) 1N2007, (.7 X 5 +3.5V) forward biased in series
(1) 300 ohm 3 watt resistor (Rs) in series
A 70 mA load at 135V tap.
I calculated :
max Iz = 5 watt/ 22 volts = .227A - .07A (load)
Rs(min) = (Vs- Vz)/(Iz-I load = (140 – 135)/(.227- .070) = 35 / .157 = 223 ohms
Rs (wattage) = P = I (sqr) x R = (.227 X .227) X 223 = (.025) X 223 = 5.5 watts
Is there an error in my calculation?
Obviously they used a higher value Rs which lowered the wattage required. My question is how did they pick the value of 300 ohms.
Is there a rule of thumb when selecting Rs, as opposed to using the minimum value and adding resistance, trial and error, to get a reasonable wattage?
If I increase Vs (Supply) to +200V, this will also increase my wattage rating of components. Should I add more Rs resistance, or add more zeners?