A
Aubrey McIntosh
- Jan 1, 1970
- 0
A circuit that I grabbed off the web, probably from Olimex, has a 100
ohm resistor after the +5 connector, and then it has a 1N4148 reverse
biased, and a 1N3734A 5.6V zenner (of course, reverse biased). I
assume that these are all there to protect things just in case some
Saturday afternoon carelessness gets spilled on the bench.
Right now, I have detailed my BOM with Mouser parts 78-1N4734A and
78-1N4148 parts.
I thought that if the 0 and +5 are connected wrong, that the Zener
would then be forward biased and conduct as a normal diode. So, I
would not have put the 1N4148 into the circuit. I don't see anything
that enlightens me in the data sheet about the forward conducting
current of the Zener.
Why put in two diodes?
ohm resistor after the +5 connector, and then it has a 1N4148 reverse
biased, and a 1N3734A 5.6V zenner (of course, reverse biased). I
assume that these are all there to protect things just in case some
Saturday afternoon carelessness gets spilled on the bench.
Right now, I have detailed my BOM with Mouser parts 78-1N4734A and
78-1N4148 parts.
I thought that if the 0 and +5 are connected wrong, that the Zener
would then be forward biased and conduct as a normal diode. So, I
would not have put the 1N4148 into the circuit. I don't see anything
that enlightens me in the data sheet about the forward conducting
current of the Zener.
Why put in two diodes?