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- Jan 21, 2010
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Make the assumption that you need to provide about 40% more energy into the battery to charge it. So to put 550 mAh into a battery in 6 hours you would need to supply a charge current of (550*1.4)/6 = 128mA
128mA is more than your panel can supply.
If you set the constant current sink in the design you have for 130mA (or thereabouts) and use a solar panel capable of maybe 400mA or more then you should be able to guarantee an appropriate charge current on most reasonably sunny days of the year in 6 hours.
128mA is more than your panel can supply.
If you set the constant current sink in the design you have for 130mA (or thereabouts) and use a solar panel capable of maybe 400mA or more then you should be able to guarantee an appropriate charge current on most reasonably sunny days of the year in 6 hours.
