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Watts vs Amps

M

Mick and Janet

Jan 1, 1970
0
I have seen a few solar panels for charging your 12v car battery. The
really cheap ones output 200-500 milli amps whilst the larger panels output
10watts. How do you convert the 10w into amps?

I have a series of 12 garden lights that come on at night. I was hoping
to get rid of the power inverter and run them direct from a 12v car battery.
At the moment there is a 70w transformer to power 10 small lights. Assuming
they come on for 3 hours a night, thats 210w a day that is needed.

How do I convert those 210w back into amps, so I can work out how big a
battery I need, and how big the panel needs to be.


Thanks

Mick
 
A

Anthony Matonak

Jan 1, 1970
0
Mick said:
I have seen a few solar panels for charging your 12v car battery. The
really cheap ones output 200-500 milli amps whilst the larger panels output
10watts. How do you convert the 10w into amps?

Volts x Amps = Watts
Watts / Volts = Amps
Watts / Amps = Volts

One milliamp = 1/1000th of One Watt

Anthony
 
G

Gymmy Bob

Jan 1, 1970
0
One milli-Helen is the beauty to launch one ship.
 
G

Gymmy Bob

Jan 1, 1970
0
To combine time and power (watts) you multiply them together (as you did)
and come up with watthours, not watts.

70W x 3 hours = 210 watthours

The time is not related to your calculation.

Watts (power) is the rate you are using the electricity (flow of water in
your hose)

watthours (energy) is the amount of energy used (puddle at the end of your
hose)

amps (current) is the speed the water is travelling in your hose

volts (voltage) is the pressure of the water from the tap
 
D

Damn Dan

Jan 1, 1970
0
Mick and Janet said:
I have seen a few solar panels for charging your 12v car battery. The
really cheap ones output 200-500 milli amps whilst the larger panels output
10watts. How do you convert the 10w into amps?

I have a series of 12 garden lights that come on at night. I was hoping
to get rid of the power inverter and run them direct from a 12v car battery.
At the moment there is a 70w transformer to power 10 small lights. Assuming
they come on for 3 hours a night, thats 210w a day that is needed.

How do I convert those 210w back into amps, so I can work out how big a
battery I need, and how big the panel needs to be.

The basic formula is W = I*V (Watts = Current * Volts). In order to charge
a 12V battery, "12V solar panels" actually produce more than 12V. They're
usually 14V or higher. It should say on the panel when you buy it what
actual voltage to expect. So, assuming the 10W panel you saw has, say, 15V,
you would plug that into W = I*V to get I = 0.6667A (or 666mA).

You have a slight misunderstanding of wattage. A watt value cannot be
increased by multiplying by time. An analogy I like to use is thinking of
wattage as a speed measurement. If you're going 60mph for 3 hours and you
want to know how fast you're going after 3 hours, it's still 60mph.
Similarly, if you're using 70W for 3 hours, you're still using 70W at the
end. If you want to measure a quantity of energy, however, that's when you
multiply by time. Just like in your car, if you want to measure how far
you've gone, you multiply your speed by time. So here the analogy is
Wattage is to Speed as Energy Used is to Distance Driven. So, by
multiplying 70W by 3 hours, you get 210Wh (watt-hours), which is very
different than 210W. A value of Watt-hour is an actual quantity of energy
while a Watt represents real-time power usage.

If you already knew all that and you just forgot to add the "h" onto the end
of W, then my apologies for such a long winded explanation. So for your 70W
system, you need to make sure you have a battery than can easily handle a
210Wh drain every night. If you're using a 12V battery, it'll have to put
out 5.83A (5.83A = 70W/12V) for 3 hours a night, which is 17.5Ah (17.5Ah =
5.83A * 3 hours). Assuming you intend to charge that battery during the day
with a solar panel, you need to make sure your panel can produce at least
210Wh during the course of the day. So assuming 4 hours of good sunlight,
you'd need a 52W panel to do the job. That number will vary depending on
how much sun you get in your area.
 
M

Mick and Janet

Jan 1, 1970
0
Dan,
Thanks for your clear simple explination below. I was misunderstood
between watt hours and watts, but it makes sence now. It is interesting to
see how big the panel needs to be just to power a few garden lights. I was
hoping the 10w panel would have been enough. The cost of the panel I saw was
AU$150, so if i bought 5 of them, thats $750 to power my garden lights!
Obviously I could get a cheaper 50w panel but for the sake of my
calculation...
I pay 17c per kwh here, so with 210watt hours per night x 365 = 76kwh x
0.17 = $13 a year to light them! I dont think I will continue my experiment.

I am getting quotes at the moment to convert my house to a solar grid
connected system. I was in the mind set of whats the point collecting solar
at 12v, then using a transformer to get upto 240v, then ultimately transform
a portion back to 12v to power the lights. I had thought I could get a
seperate small system just for the lights, but I dont think I will bother.

Thanks again,

Mick
 
G

Gymmy Bob

Jan 1, 1970
0
Don't forget to calculate in losses.
That adapter you use to power your lights is probably about 40-60% efficient
and you leave it plugged into the wall 24/7 drawing about 4-5 watts.
 
A

Anthony Matonak

Jan 1, 1970
0

Er, sorry, my bad. It is, of course, a fraction of
an amp, not a watt. :)

Note to self: gotta proofread.

Anthony
 
G

Gymmy Bob

Jan 1, 1970
0
That was all you could measure with your 10 ohm ammeter in series silly!
 
G

Gymmy Bob

Jan 1, 1970
0
Well I'll be darned. You can agree with my figures, recalculate them for
yourself and repeat them on the next line, with the same result each time,
and still say I was wrong, and still be a jackass about it. Better reread
what you posted again and think about it. You are really discrediting
yourself AGAIN....LOL

BTW if you used the 200 mAmp scale on your digital multimeter and your
multimeter has a F.S. sensitivity of 199.99 mV the apparent, external
resistance will be

0.2V / 0.2 A = 1 ohm
If you are using a home meter it may likely be a 1.999 V F.S. and that makes
it a 10 Ohm impedance.

Now if you used the 2.000 Amp F.S. scale to read 5 mA then you have
confirmed what I thought the first time you posted.

Give it your best...LOL
 
G

Gymmy Bob

Jan 1, 1970
0
Buh bye troll. At least you could have tried to sound real. You may have
sucked me into more posts and gotten better marks.

Trolling effort 2 out of 10
Trolling technique 3.5 out of 10
 
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