O.K Duke,
Let's take it step by step to solve this problem,from #5,the answer was given by Ratch at #6
We can treat this simple circuit as we do with resistors only.
Equivalent cap and resistors values:
The calculations of capacitors in parallel is like that of resistors in series(addition).
The calculations of capacitors in series is like that of resistors in parallel.
Voltage divider for caps and for resistors:
For 2 resistors in series we have Vr1=VxR1/(r1+r2)
For 2 capacitors in series we have Vc1=VxC2/(c1+c2)
Note the difference!!!
I don't want to go into how it is derived,if you need to,we can do that as well.
So Lets calculate,,
for C3 and C4 ,which are in series, we get C34=(C3xC4)/(C3+C4)=(2x2)/2+2=1.
C2 is in parallel with the above calculated C34 thus we get C234=C2+C34=1+1=2.
Calculating voltages :
on C1:
VC1 =VxC234/(C1+C234)=12x2/(1+2)=8V
on C2
VC2=VC234=12-8=4V
on C3,C4
since C3=C4 we get VC3=VC4=VC234/2=4/2=2V
Note also that the charge on each capacitor in a series connection is the same!
It takes much longer to write it down than to calculate it by heart,
that is the reason I changed the values and circuit to give an easy round numbers solution.
Hope it clarifies things.