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Voltage Drops???

S

Sports One

Jan 1, 1970
0
How do you calculate voltage drops?


Ex. 540 foot run of 480 volt 4/0 copper with a load of 200amps.


Thanks in advance for any help you can give
 
C

Cougercat

Jan 1, 1970
0
4/0 Cu has a resistance of .0490 ohms/1000 feet.

So....540 ft/1000ft = .54

..54 x .0490 = .02646 ohms resistance per 540 foot chunk.

Vd = I R

Vd = 200 x .02646

= 5.292 volts drop. or 1.1%
 
S

SueMarkP

Jan 1, 1970
0
Cougercat said:
4/0 Cu has a resistance of .0490 ohms/1000 feet.

So....540 ft/1000ft = .54

.54 x .0490 = .02646 ohms resistance per 540 foot chunk.

Vd = I R

Vd = 200 x .02646

= 5.292 volts drop. or 1.1%

But the current goes there and back. So if the source and destination are
540 feet apart, you need to double the voltage drop because its going
through 1080 feet of wire.
 
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