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Voltage doubling?

Discussion in 'Electronic Basics' started by Glenn Ashmore, Feb 14, 2005.

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  1. I have a 1000 PSI pressure transducer that outputs a 0 - 5VDC signal. I
    want to double the voltage to display the pressure on a cheapo LCD panel
    meter that reads 0 - 20V. How can I change the signal so that it reads
    correctly on the meter? i.e. 800PSI = 4V in = 8V out.

    Glenn Ashmore

    I'm building a 45' cutter in strip/composite. Watch my progress (or lack
    there of) at:
    Shameless Commercial Division:
  2. John Fields

    John Fields Guest

    | >---+--->0-10V
    +--|-/ |
    | |

    R can be anything as long as they're both the same and the opamp can
    supply the drive current. 100k would probably be fine, but I'd go
    with 10k if I could. If you get an opamp with rail-to-rail inputs and
    outputs you'll be able to use a single 12V supply, otherwise you'll
    need a positive supply high enough to give the opamp the headroom it
    needs to get the output to +10V and a negative supply low enough to
    keep the output from bottoming out before the input gets to zero
  3. Clarence_A

    Clarence_A Guest

    Simple Operational Amplifier? Works for me!
  4. Rich Grise

    Rich Grise Guest

    Most cheapo panel meters I've seen actually have an input voltage of 0-.2
    V, and you scale it with input resistors. For example, to display 0-2V,
    you'd use an input divider of 900K/100K for an input of 1M, and a division
    factor of 10. So, if you want it to display 10 when the input is 5, you
    need to divide 5V down to 100 mV. That's assuming 200 mV full-scale.

    If your panel meter really really really expects 20V at its input, you
    have a whole nother project on your hands.

    But seriously, look for input range jumpers or something of that nature.
    It's probably as simple as selecting a resistor.

    And the decimal point is usually as simple as grounding one tie point. :)

    Good Luck!
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