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Very Simple Electronics Question

Discussion in 'General Electronics Discussion' started by Electronics2014, Feb 19, 2014.

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  1. Electronics2014

    Electronics2014

    3
    0
    Feb 19, 2014
    I am making a circuit which will run of a 9V. All l do is connect the 9V battery to the loud speaker and it plays a siren noise.

    Considering that l may only use this very infrequently and that the battery is ALWAYS connected to the terminals, l just wanted to know in your opinion which of the circuits A or B would be best and optimum for battery power conservation. I should not think that there would be any difference but just wanted to check with you.

    Thank you
     

    Attached Files:

  2. GonzoEngineer

    GonzoEngineer

    321
    2
    Dec 2, 2011
    No difference, you will not draw power if the circuit is open.
     
  3. Divedeep

    Divedeep

    57
    0
    Feb 2, 2014
    Circuit A is the most practical as it saves on a second switch.

    Current cannot flow through the circuit until the circuit is completed by pressing the switch. Disconnecting the second terminal of the battery will do nothing to help conserve power.
     
  4. BobK

    BobK

    7,682
    1,686
    Jan 5, 2010
    What makes you think connecting a 9V battery to a speaker will make a siren noise?

    Bob
     
  5. Electronics2014

    Electronics2014

    3
    0
    Feb 19, 2014
    Thanks, it only occurred to me as sometimes you put brand new batteries in a device, not use it and leave it for a month and then you find the batteries are completely dead/drained. hence, my original question. Thanks for the responses.
     
  6. Electronics2014

    Electronics2014

    3
    0
    Feb 19, 2014

    It is a device that has a circuit built in the speaker which produces the two alternating frequency tones. That was the only symbol l could find without drawing whole schematic out.
     
  7. BobK

    BobK

    7,682
    1,686
    Jan 5, 2010
    Oh, okay, so not a speaker after all, but a siren module.

    Bob
     
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