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The bias current compensating resistor (R1) is placed in series with the noninverting (+) input to compensate for bias current voltage drops in the divider network: And should be the same as the parallel sum of R2 and R3..
true, and in this case the bias current is zero, and you have correctly calculated the voltage drop across it must be zero.
So if the voltage (with respect to ground) at one end of the resistor is 100mV, what is the voltage at the other end (I.e. At the noninverting input of the op amp)?
And therefore, what must be the voltage the feedback loop will have the op-amp try to maintain at the inverting input
My course notes show that:
V−=V+ because the op-amp is ideal and V+=Vin
So is this as simple as as saying V- =100mV ???
Steve voltage on Non Inverting will be 100mV.
The voltage on the other input will also be 100mV ( V−=V+ because the op-amp is ideal )
Steve voltage on Non Inverting will be 100mV.
The voltage on the other input will also be 100mV ( V−=V+ because the op-amp is ideal )