# Line slope calculator 2x-5y=-10

**Straight line given by points A[0; 2] and B[5; 4]**

## Calculation:

**Slope-intercept form of line:**y = 0.4x+2

**Canonical form of the line equation:**2x-5y+10 = 0

**Parametric form of the line equation:**

x = 5t

y = 2t+2 ; t ∈ R

**Slope:**m = 0.4

**Slope angle of line: φ =**21°48'5″ = 0.3805 rad

**X intercept:**x

_{0}= -5

**Y intercept:**y

_{0}= q = 2

**Distance line from the origin:**d

_{0}= 1.857

**The length of the segment AB: |AB| =**5.3852

**Vector: AB =**(5; 2)

**Normal vector: n =**(2; -5)

**Midpoint of the segment AB: M =**[2.5; 3]

**Perpendicular Bisector equation:**5x+2y-18.5 = 0

**Vector OA = (0; 2) ; |OA| = 2**

**Vector OB = (5; 4) ; |OB| = 6.4031**

**Scalar product OA .OB = 8**

**Angle ∠ AOB = 51°20'25″ = 0.8961 rad**