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Trouble building an Oscillator

Discussion in 'General Electronics Discussion' started by Chad Potter, Jan 6, 2014.

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  1. Chad Potter

    Chad Potter

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    Jan 6, 2014
    I need someone to help me figure out a schematic used for constructing a square-wave oscillator over any form of private chat. Facebook, Skype, oovoo, even this site. It doesn't matter, I just really need someone's help within the next few hours. Details (including the schematic) will be provided in private messaging. Thanks :)
     
  2. davenn

    davenn Moderator

    13,901
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    Sep 5, 2009
    hi chad
    welcome to the forums :)

    did you try google there's many circuits available

    google circuit for a square wave oscillator and have a look at the choices

    cheers
    Dave
     
  3. Chad Potter

    Chad Potter

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    Jan 6, 2014
    Thanks Dave :)

    As a matter of fact, I have looked all around google. There is one specific type I'm trying to create and it's creator doesn't exactly give a full description of the connections :p thus my dilemma.
     
  4. (*steve*)

    (*steve*) ¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥd Moderator

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    Jan 21, 2010
    Post the schematic and the problems you're having (is it identifying which lead is which?).

    We can't promise instant response, but there's a few people around now, so you might be lucky.
     
  5. Chad Potter

    Chad Potter

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    Jan 6, 2014
    [​IMG] My problem is that I don't know how to connect the potentiometers and 9v power jack to the circuit board.
     
  6. Chad Potter

    Chad Potter

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    Jan 6, 2014
    And crap, here's the schematic that was supposed to be in my last comment [​IMG]
     
  7. (*steve*)

    (*steve*) ¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥd Moderator

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    Jan 21, 2010
    The long end of the battery on the diagram is the +ve end. The short end is the -ve end.

    The pins 7 and 4 on your IC (from your schematic) connect to the points labelled +4.5 and -4.5. All the ground symbols are conected together,.

    Is that what you're having problems with?
     
  8. Chad Potter

    Chad Potter

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    Jan 6, 2014
    7 to +4.5 and 4 to -4.5?
     
  9. davenn

    davenn Moderator

    13,901
    1,971
    Sep 5, 2009
    yes, correct

    Do you understand what they are doing there ?

    Taking a 9V battery and creating a + and - rail power supply
    Feeding the battery to the top and bottom of those 2 10k resistors
    they are called a voltage divider in that configuration, and they generate a 0V (GND) rail at the point between the 2 resistors

    cheers
    Dave
     
  10. Chad Potter

    Chad Potter

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    Jan 6, 2014
    Thanks!! Now where does the negative end of the LED go?
     
  11. davenn

    davenn Moderator

    13,901
    1,971
    Sep 5, 2009
    just as it is shown

    the LED goes across the battery with the 4.7k resistor in series

    be aware there is no power switch shown, therefore there is power to the LED and the oscillator circuit ALL the time
    A switch should go between the top of the battery and that "T" connection above it

    Dave
     
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