# Trouble building an Oscillator

Discussion in 'General Electronics Discussion' started by Chad Potter, Jan 6, 2014.

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Jan 6, 2014
I need someone to help me figure out a schematic used for constructing a square-wave oscillator over any form of private chat. Facebook, Skype, oovoo, even this site. It doesn't matter, I just really need someone's help within the next few hours. Details (including the schematic) will be provided in private messaging. Thanks

2. ### davennModerator

13,901
1,971
Sep 5, 2009
welcome to the forums

did you try google there's many circuits available

google circuit for a square wave oscillator and have a look at the choices

cheers
Dave

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Jan 6, 2014
Thanks Dave

As a matter of fact, I have looked all around google. There is one specific type I'm trying to create and it's creator doesn't exactly give a full description of the connections thus my dilemma.

4. ### (*steve*)¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥdModerator

25,500
2,840
Jan 21, 2010
Post the schematic and the problems you're having (is it identifying which lead is which?).

We can't promise instant response, but there's a few people around now, so you might be lucky.

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Jan 6, 2014
My problem is that I don't know how to connect the potentiometers and 9v power jack to the circuit board.

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Jan 6, 2014
And crap, here's the schematic that was supposed to be in my last comment

7. ### (*steve*)¡sǝpodᴉʇuɐ ǝɥʇ ɹɐǝɥdModerator

25,500
2,840
Jan 21, 2010
The long end of the battery on the diagram is the +ve end. The short end is the -ve end.

The pins 7 and 4 on your IC (from your schematic) connect to the points labelled +4.5 and -4.5. All the ground symbols are conected together,.

Is that what you're having problems with?

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Jan 6, 2014
7 to +4.5 and 4 to -4.5?

9. ### davennModerator

13,901
1,971
Sep 5, 2009
yes, correct

Do you understand what they are doing there ?

Taking a 9V battery and creating a + and - rail power supply
Feeding the battery to the top and bottom of those 2 10k resistors
they are called a voltage divider in that configuration, and they generate a 0V (GND) rail at the point between the 2 resistors

cheers
Dave

6
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Jan 6, 2014
Thanks!! Now where does the negative end of the LED go?

11. ### davennModerator

13,901
1,971
Sep 5, 2009
just as it is shown

the LED goes across the battery with the 4.7k resistor in series

be aware there is no power switch shown, therefore there is power to the LED and the oscillator circuit ALL the time
A switch should go between the top of the battery and that "T" connection above it

Dave