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Theory: open/shor-circuit time-constant method...

Discussion in 'Electronic Basics' started by Redentore, Aug 23, 2007.

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  1. Redentore

    Redentore Guest

    Hi! I'm studying the open and short-circuit time-constant method and I've a
    little problem.
    When I have a capacitive loop (or a loop with only capacitors and controlled
    voltage source), since loop voltage should be 0, one capacitor is not
    indipendent, so it dosn't produce a pole (so from loop of 4 capacitors i get
    3 poles).
    The problem is: how I deal with this in the circuit? When I study a circuit
    with a capacitive loop, what change I have to do to get the correct result
    (I change the loop? I should transofrm the circuit? I have a different
    equation?);
    the usual a1 = SUM( Ci*Ri(O) ), for the high frequency analysis, and b1 =
    SUM( 1/Ci*Ri(S) ), for low frequency, don't work.
    Somene can help me out?
    Thank you!
     
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