# Switches in Series Combination?

Discussion in 'Electronic Basics' started by DaveK, Apr 25, 2007.

1. ### DaveKGuest

Use a 2 pole rotary switch to give you the combinations, and use
diodes
for the selection of any 2 switches or any one.. or all in series.
basically, just tie them all in series.. and use diodes to select
the pairs.
The diode will prevent back feed to other combinations.
The circuit will have to be DC.

This was a reply that I received in regards to my original question
below. The problem is I;m not quite sure how to set it up. Can anyone
show it on a schematic? Thank you for your time

Original Question
Can anyone recommend a rotary switch, transistors, Ic's, or any
component that may work for the following situation?
I have three momentary switches in series (two mercury and one reed).
What I would like to do is to be able to have the ability to allow
any
one switch work alone, any combination to allow 2 to work in series,
and all three to work in series as they are now? II have limited
space
and would like to use the lowest profile component possible. I have
minimal experience with the different type of components, but have
time and a willingness to learn.

3. ### ehsjrGuest

Here's how I would do it, provided my diagram below
accurately captures what you want:

Assuming the seven possibilities above are what you
want, you could wire it this way, with a toggle switch in
parallel with each momentary switch:

/ / /
+--o o--+ +--o o--+ +--o o--+
| Tsw1 | | Tsw2 | | Tsw3 |
| | | | | |

That way, any momentary switch can be removed from affecting
circuit function and replaced by a connection to the next.
3 minature toggle switches will take up a lot less space
than 2 rotary switches.

By the way, the diagrams are shown using DC, but it will
work fine with AC or DC.

Ed

4. ### DaveKGuest

Wow! Thank you so much!
You made it very easy for me to understand, so much that I don't even
have to ask any further question. This will work just great.

Thanks Again,
Dave K

5. ### ehsjrGuest

You're welcome.
Ed