SN74HC595N Shift Register Problem

Hello,

I'm testing the shift register. The circuit is the same as the attachment pdf file. I want to be able to control one bright led and shift it from QA to QB (Only 1 led will be bright at a time step)
To be clear, I'll press the switch S1(SER/Data In pin) to input 5V data to the shift register. Next, I'll press S3 (SRCLK) to shift 5V to QA and then press the S2 (RCLK/Latch pin) to see the led which is connected to QA shine. I'll keep doing this to see only QB shine.... only QC shine... until only QH and then return back to QA

The problem is when I connected all of this stuff, all LEDs are bright and I can't control anything. Did I make any mistakes?

Thanks
BlackMelon

PS: This is the datasheet of SN74HC595N
http://www.es.co.th/Schemetic/PDF/SNX4HC595.PDF

 

Thank you Kris. Right now, I want to modify the circuit to be shift-restore (rotate the data of Q4 back to Q1). Q1 to Q4 is connected to LED. The result that I want to see is pressing only 1 button and the bright LED will be shifted right until it meets the last LED then return back to the first one. My idea is to do the circuit as an attachment here. The problem is the data pin (which should be the "D" of the first flip flop).

At the very beginning, the data pin should be high then I'll press the shift key to shift the high state from data pin to Q1. After I shifted the data from the data pin to Q1, the data pin should be low. My reason is from this point on, it will continuously shift more low states from data to Q1 (if I give a clock and latch signal) and the bright led will be shifted to the right

Here is the problem:
1) After the bright led is the Q4 and the data is low, will it be a dead short which will burn my stuff?

2) If so, is there any efficient way to solve this except putting a relay to disconnect the data pin out when the bright LED is the 4th LED? (Because a relay is expensive )

 

I'm sorry for making confusion. I mean 1 LED is on and the rest is off.
1st state: Q1=1 the rest are off
2nd state: Q2=1 the rest are off
.....
Then rotate back to Q1


I come up with a new idea too in the attachment, is it valid?

(The number in sequence like 1,0,1 means that at the first state, this node is 1... the next state it will be 0 and the 3rd state it will be 1 again.... It doesn't mean that I use any external circuit to force that node to be that sequence)

 

I found that the CD4017 is much cheaper than a shift register. :v :v :v
Thank you everyone

 

The shift register CD4017 works magnificently!! The clock button is connected to a microcontroller. As the bright led shift from the very left LED to the right(4th led), the controller will count 1 to 4 and then count back to 1

The only problem right now is the Vcc. When the 5V is supplied to both microcontroller and shift register, the shift register will work first. I mean if I give a clock, the shift register will shift a display LEDs for me but the microcontroller have to wait until 5 minute to start counting up. Is there any good way to solve this?





PS: I was trying an RC time constant to delay 5V to CD4017 (I also add a buffer after the RC circuit otherwise the voltage might be decrease by resistor when the capacitor is full). The result does not satisfy me much. When I press the clock button 3 times, the LEDs are still off. I thought that the RC delayed for me already. After few seconds, the bright LED is the third one which means the CD4017 has shifted the 5V data even the supply voltage is lower than 5V.

 

Yes but not that long. Might be 10seconds. My microcontroller ports are full right now so I can't lose any ports to do the job.