D
D Yuniskis
- Jan 1, 1970
- 0
Hi,
I have an SMT design that must support three R choices
at final assembly. R1 < R2 < R3
Differential stuffing is not an option. Boards need
to be identical up to final assembly/test.
One option is to install three R's in a series chain:
R1, R2 - R1, R3 - (R2 + R1) and short none, the last, or
the last *two* R's depending on the configuration desired.
Another approach is to arrange three paralleled resistors such
that R1 is formed by R3 || Ra || Rb and R2 formed by R3 || Ra.
Then, removing Rb and possibly Ra, as required.
The first approach could be accomplished with solder switches
on the board -- but that eats up real estate (this is a *tiny*
board!). Bridging R's with shunts seems like it could lead
to components becoming "unsoldered" in the process.
The second approach could possibly be accomplished by *cutting*
the R's in question (gasp!).
Are there other approaches that I should evaluate?
Thx,
--don
I have an SMT design that must support three R choices
at final assembly. R1 < R2 < R3
Differential stuffing is not an option. Boards need
to be identical up to final assembly/test.
One option is to install three R's in a series chain:
R1, R2 - R1, R3 - (R2 + R1) and short none, the last, or
the last *two* R's depending on the configuration desired.
Another approach is to arrange three paralleled resistors such
that R1 is formed by R3 || Ra || Rb and R2 formed by R3 || Ra.
Then, removing Rb and possibly Ra, as required.
The first approach could be accomplished with solder switches
on the board -- but that eats up real estate (this is a *tiny*
board!). Bridging R's with shunts seems like it could lead
to components becoming "unsoldered" in the process.
The second approach could possibly be accomplished by *cutting*
the R's in question (gasp!).
Are there other approaches that I should evaluate?
Thx,
--don