S
Steve
- Jan 1, 1970
- 0
Hi everyone!
I need some advice regarding closing the feedback loop of a halfbridge
voltagemode smps.
I need to calculate the power circuit gain. As far as I know, this is
determined by taking transformer peak secondary voltage divided by
modulator pwm-ramp amplitude. In my case, there are 2 secondary
windings which both provides 75V peak (at 220Vac mains). So, 75
divided by 2.5 which is the pwm ramp amplitude, comes out to 30. Each
secondary are connected to a fullwave buck-output filter and
rectification.
The error-amp is powered between both secondary rails. The supply will
regulate at +/- 50Vdc. The error-amp is hooked up so it will actually
"see" an output of both rails, which is 100V. (It's using -50Vdc as
reference)
So, to my question #1: As far as I can see, this arrangement results
in doubled power circuit gain, correct?
Question #2: Is there any other difference in placing the error-amp in
this way compared to placing it just to "see" one of the rails and use
secondary ground as reference.
Excuse for describing this rather clumsy...Please forgive me for that.
If there are any kind person out there who think he/she has the time
to look into my questions, I'll gladly provide you with additional
information if something's unclear in my description.
Best regards,
Stefan
I need some advice regarding closing the feedback loop of a halfbridge
voltagemode smps.
I need to calculate the power circuit gain. As far as I know, this is
determined by taking transformer peak secondary voltage divided by
modulator pwm-ramp amplitude. In my case, there are 2 secondary
windings which both provides 75V peak (at 220Vac mains). So, 75
divided by 2.5 which is the pwm ramp amplitude, comes out to 30. Each
secondary are connected to a fullwave buck-output filter and
rectification.
The error-amp is powered between both secondary rails. The supply will
regulate at +/- 50Vdc. The error-amp is hooked up so it will actually
"see" an output of both rails, which is 100V. (It's using -50Vdc as
reference)
So, to my question #1: As far as I can see, this arrangement results
in doubled power circuit gain, correct?
Question #2: Is there any other difference in placing the error-amp in
this way compared to placing it just to "see" one of the rails and use
secondary ground as reference.
Excuse for describing this rather clumsy...Please forgive me for that.
If there are any kind person out there who think he/she has the time
to look into my questions, I'll gladly provide you with additional
information if something's unclear in my description.
Best regards,
Stefan