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SMPS feedback loop phase and gain margin

Discussion in 'Electronic Design' started by Jamie Morken, May 21, 2008.

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  1. Jamie Morken

    Jamie Morken Guest


    What is a good way to increase the stability of a SMPS feedback loop?
    I have a SMPS that uses this algorithm:

    if inductor current > current_limit, pulse off

    Duty cycle = ((desired voltage - current voltage) * gain) - (Inductor
    current * gain2)

    I am not sure how to put in the analog or digital adjustments for making
    sure the feedback loop is stable.

    I am reading up on these pages but am not sure how to implement this on
    a PCB, either analog or in an FPGA:

  2. MooseFET

    MooseFET Guest

    You didn't say what sort of DC-DC this is. What you are using as a
    control equation makes me think it is a simple bucker topology. The
    equation you have shown won't yeld a very good load regulation.

    If this is a design with a continuous inductor current, think of the
    PWM's signal as having been magically low pass filtered so that you
    cant see the switching and only see (Duty * Vin)

    (Duty * Vin) ----)))))-----+------- Load

    As you can see, from (Duty * Vin) to the load we have a LC filter. If
    you assume that your equation for doing the control is feeding into a
    linear system, you have a fairly simple way to make a Bode plot of the
    system. The issue of the delay in the modulator is not taken into
    consideration in this plot.

    To deal with the modulator, you will usually find that assuming a
    simple linear delay of 1/2 of a switching cycle will get you into the
    right ball park.

    Basically, you want the duty cycle to be controlled by a PID
    controller running from the error signal. Your term where you brought
    the inductor current into the equation is trying to do the "D" part by
    saying that the current in the inductor tells you the rate of change
    in the capacitor (C1) voltage.

    Using the inductor current in this way doesn't lead to very good
    performance because you don't get to bring the high frequencies of the
    load current into the "D" term. This greatly reduces your ability to
    track a sudden changes in the load.
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