Connect with us

Series/Parallel of 10 resistors question

Discussion in 'Electronic Design' started by John S, Oct 19, 2011.

Scroll to continue with content
  1. ehsjr

    ehsjr Guest

    Oh crap. That's 2 _more_ things I missed. I thought the op wanted
    simple series/parallel and practical solutions, not complex arrays
    & theoretical solutions.
    Grumble. Displeased with myself, but glad you posted.

  2. Martin Brown

    Martin Brown Guest

    Yes. I agree. I was slightly pleased to see it and the way I read it
    confirmed that my construction was sufficient. I did say that I wasn't
    sure if some networks of deltas might generate some new values.
    I agree with Jon (this was the sort of net that I was worried about).

    But this particular one is too symmetrical and does not contribute any
    new values to the sequence. A basic symmetry argument shows that the two
    nodes are at V/3 and 2V/3 and the overall impedance is R. If you draw it
    right the equipotential surfaces become clear.

    I think the first one that could introduce a novel value requires one
    extra resistor so one leg has 3R in it. Can anyone find or derive the
    full sequence for every possible network from identical resistors?

    I'd also be interested in the number of unique values.

    The two that my construction does not generate for N=4 are

    R||R+R||R and (R+R)||(R+R)

    I think that is all of them

    I haven't so far been able to sketch all the missing N=5 networks.
    It is obviously at least 4.

    It seems clear that for any composite number PQ less than the total
    number of resistors N you can take them in groups of P or Q and apply
    the series parallel rule to the clumps which definitely generates new
    networks. 6 is the first composite with distinct factors.
  3. Jon Kirwan

    Jon Kirwan Guest

    Bitrex nailed a good paper here:

    Take a look. It's all you could hope to want, I think, if
    you include the references as well.

  4. Martin Brown

    Martin Brown Guest

    Thanks! Not only that but some of the results are applicable to software
    testability (a subject I am very interested in).
  5. Jon Kirwan

    Jon Kirwan Guest

    Please share! What parts relate to that (what do you _see_
    in your mind about this?) I'm very curious.

  6. mike

    mike Guest

    How many ways can you hook up one resistor?
    How many unique ways can you add a resistor to make a composite resistor?
    TWO, series or parallel.
    For each of the two composite resistors, how can you add a resistor
    to make a new composite resistor?
    TWO, series or parallel.
    For each of the 4 possible composite resistors, how can you add a resistor
    to make a new composite resistor?
    repeat 'till you run out of resistors...add 'em up.

    Is it not that simple?

    For unequal resistors, gets much more complicated,
    but the same concept should work.
  7. Tauno Voipio

    Tauno Voipio Guest

    This method leaves out the combinations where the new
    composite is built of composite blocks, as you're adding
    one resistor at a time. For instance, it does not generate
    a series connection of two parallel-connected blocks.
  8. John S

    John S Guest

    Read the thread and concentrate on those posts by Martin Brown. Perhaps
    they will answer your question.
  9. Guest

    The correct answer is:


    Which is:

    One novemoctogintillion,
    eight hundred thirty-six octooctogintillion,
    two hundred thirty-nine septoctogintillion,
    two hundred three quinoctogintillion,
    forty quattuoroctogintillion,
    thirty-four treoctogintillion,
    two hundred fifty duooctogintillion,
    two hundred forty-six unoctogintillion,
    six hundred twenty-one octogintillion,
    four hundred thirty-five novemseptuagintillion,
    two hundred forty-two octoseptuagintillion,
    four hundred ten septseptuagintillion,
    one hundred sexseptuagintillion,
    three hundred fifty-two quinseptuagintillion,
    fifty-two quattuorseptuagintillion,
    twenty treseptuagintillion,
    six hundred twenty duoseptuagintillion,
    three hundred forty-one unseptuagintillion,
    four hundred thirteen septuagintillion,
    five hundred seventy-two novemsexagintillion,
    five hundred seventy-two octosexagintillion,
    five hundred sixty-two septsexagintillion,
    four hundred fifty-two sexsexagintillion,
    four hundred thirteen quinsexagintillion,
    eleven quattuorsexagintillion,
    two hundred four tresexagintillion,
    two hundred five duosexagintillion,
    two hundred forty-five unsexagintillion,
    two hundred forty-eight sexagintillion,
    five hundred sixty-two novemquinquagintillion,
    four hundred seventy-six octoquinquagintillion,
    two hundred forty-seven septenquinquagintillion,
    six hundred twenty-four sexquinquagintillion,
    nine hundred twenty-four quinquinquagintillion,
    nine hundred twenty-four quattuorquinquagintillion,
    six hundred eighty-two trequinquagintillion,
    three hundred forty-six duoquinquagintillion,
    seven hundred twenty-four unquinquagintillion,
    eight hundred seventy-five quinquagintillion,
    nine hundred thirteen novemquadragintillion,
    nine hundred forty-eight octoquadragintillion,
    two hundred seventy-five septenquadragintillion,
    two hundred forty-seven sexquadragintillion,
    six hundred forty-six quinquadragintillion,
    eight hundred twenty-four quattuorquadragintillion,
    three hundred fifty-nine trequadragintillion,
    two hundred forty-five duoquadragintillion,
    one hundred twenty-three unquadragintillion,
    four hundred twenty-three quadragintillion,
    eight hundred fifty-two novemtrigintillion,
    four hundred fifty-six octotrigintillion,
    eight hundred forty-two septentrigintillion,
    eight hundred seventy-five sextrigintillion,
    two hundred forty-eight quintrigintillion,
    five hundred eighty-four quattuortrigintillion,
    five hundred sixty-seven tretrigintillion,
    four hundred fifty-six duotrigintillion,
    seven hundred twenty-seven untrigintillion,
    one hundred thirty-eight trigintillion,
    four hundred thirteen novemvigintillion,
    four hundred forty-seven octovigintillion,
    five hundred sixty-four septenvigintillion,
    five hundred sixty-two sexvigintillion,
    five hundred twenty-three quinvigintillion,
    four hundred fifty-nine quattuorvigintillion,
    two hundred twenty-five trevigintillion,
    nine hundred twenty-four duovigintillion,
    seven hundred twenty-four unvigintillion,
    five hundred sixty-four vigintillion,
    six hundred seventy-two novemdecillion,
    eight hundred fifty-eight octodecillion,
    two hundred seventy-two septendecillion,
    seven hundred seventy-two sexdecillion,
    seven hundred fifty-two quindecillion,
    seven hundred fifty-seven quattuordecillion,
    two hundred fifty-seven tredecillion,
    two hundred seventy-eight duodecillion,
    five hundred seventy-two undecillion,
    five hundred seventy-two decillion,
    seven hundred fifty-two nonillion,
    four hundred seventy-five octillion,
    seven hundred twenty-three septillion,
    four hundred fifty-seven sextillion,
    two hundred fifty-seven quintillion,
    two hundred seventy-five quadrillion,
    one hundred seventy-seven trillion,
    three hundred twelve billion,
    three hundred forty-seven million,
    two hundred forty-six thousand,
    five hundred thirty-four
  10. Martin Brown

    Martin Brown Guest

    The permutations in some of the equations derived there are closely
    related to the path testing coverage problem for branch decision points
    in software if you do a little bit of relabelling of the entities.

    The traditional metric is cyclomatic complexity index first derived by
    McCabe - it sort of works (it is correct for what it sets out to do).
    What it is also good for is spotting latent maintenance traps in
    inherited code. If the complexity is beyond a certain limit there is a
    very good chance that it will contain bugs.
Ask a Question
Want to reply to this thread or ask your own question?
You'll need to choose a username for the site, which only take a couple of moments (here). After that, you can post your question and our members will help you out.
Electronics Point Logo
Continue to site
Quote of the day