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Re: duty cycle and sine waves

Discussion in 'Electronic Basics' started by Jamie, Jan 23, 2011.

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  1. Jamie

    Jamie Guest

    Average voltage in a square wave? I think that would be more appropriate
    to say average in a sine wave or pulse train.

    Avg = 2/Pi; Vp = Peak Voltage; Pk = RMS*1.414;

    in any case, Vavg = Vp in a 50% duty square wave (+&-) No difference

    A pulse train, that is an ON and base line off, no (-)

    Vavg = (b/a)*Vp;
    B = ON Time, A = the time from the start of ON time to the next
    start of on time.

    In a sine wave the average is 2/pi * Vp = 0.636 * Vp

    A triangle wave:

    Vavg = Vp * .5;

    A trapezoid wave

    Vavg = A+B / 2* A *Vp

    (A) being the base line width and (B) being the Peak width and Vp
    being the Peak voltage.

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