P
Peter
- Jan 1, 1970
- 0
It appears I've confused everyone because I don't understand the equation.
i = C dV/dt represents what?
I was under the assumption that it meant: i = C (delta V / delta t)
meaning: if I start off a circuit with zero volts and ramping up the
voltage to 10 volts, that would equal my delta v. if I ramped it in 1
second, then my delta v / delta t would be equeal to 10.
So the current (i) after 1 second would be equal to C * 10
It appears dV/dt is NOT the deltas. It's more of: d/dt (V) where V is a
voltage.
Hopefully my explanation about how confused I am will help someone
understand what it is I'm trying to ask.
Thank you for all your replies, I look forward to more input.
i = C dV/dt represents what?
I was under the assumption that it meant: i = C (delta V / delta t)
meaning: if I start off a circuit with zero volts and ramping up the
voltage to 10 volts, that would equal my delta v. if I ramped it in 1
second, then my delta v / delta t would be equeal to 10.
So the current (i) after 1 second would be equal to C * 10
It appears dV/dt is NOT the deltas. It's more of: d/dt (V) where V is a
voltage.
Hopefully my explanation about how confused I am will help someone
understand what it is I'm trying to ask.
Thank you for all your replies, I look forward to more input.