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rate of change in a capacitor

P

Peter

Jan 1, 1970
0
I'm trying to understand something.


current in a capactior is given by: i= C dV/dt

if you take the deriv. of d/dt you get: i= C * (V / 1)

is this correct?


So if I have a 1mF capactior and 100 volts DC, then my instantanous current
should be: 0.1A

Plugging this into MultiSim does not give me that value.

Can someone explain this to me?


Thanks in advance!
 
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