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Question about Modelling the ESR of a Capacitor

Discussion in 'Electronic Basics' started by K2, Apr 6, 2007.

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  1. K2

    K2 Guest

    Hi Guys,

    under:

    http://www.avxcorp.com/docs/techinfo/eqtant.pdf

    you can find some basics about the 'ESR' of a Capacitor.

    A formula is shown describing the 'ESR' as: Rp/((2*Pi*f*Cp*Rp)^2+1)
    and the 'ESC' is : Cp+1/((2*Pi*f*Rp)^2*Cp)



    I guess, that the basic model looks like this:

    || __________ __________
    --------o----------||--------o-----|__________|-------|==========|----
    | || Cp | Rs Ls
    | ___________ |
    |---|___________|----|
    Rp


    My first Questions:

    Is the formula for the ESR correct??
    Paralleling Cp and Rp should result into an impedance of:
    Rp/sqrt(1+(2*Pi*f*R*C)^2)

    Or NOT????


    My second Question:

    I don't have a glue how the 'ESC' has to be calculated at all.
    What is the idea behind that?



    So long


    Karsten
     
  2. John  Larkin

    John Larkin Guest

    ESR = Rs.

    I have no idea what ESC stands for.

    Avoid tantalums. They tend to explode.

    John
     
  3. Phil Allison

    Phil Allison Guest

    "K2"

    ** The formulae applies to fig 4 which shows a perfect capacitor in
    parallel with a resistor.




    ** No.

    Fig 4 does not show what you drew.



    ** For the case shown in of fig 4 only.



    ** To make the parallel and serie scircuits bahave the same at the frequency
    of interest.

    Same impedance and same phase angle.




    ........ Phil
     
  4. Jean-Yves

    Jean-Yves Guest

    some beginning of the answer... :
    http://members.ozemail.com.au/~bobpar/k7214.pdf

    regards,
     
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