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Question about making simple voltage divider

Discussion in 'Electronic Basics' started by anonymous, Oct 25, 2003.

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  1. anonymous

    anonymous Guest

    I need to build a simple voltage divider with a variable resistor. The
    circuit has 3.2v DC and I need to install a pot so there's a variable output
    between 1v and 1.5v DC

    Assume I have 1K pot, would a 3K from +v to one side of the pot and 1500 ohm
    from other side of the pot to ground work?

  2. Impmon

    Impmon Guest

    Thank you. I was close and it does sound about right. I'll probably
    use 3.3K resistor since it's the nearest common value and 2 1K in series
    should get me 2K.
  3. Baphomet

    Baphomet Guest

    You have stated (indirectly) that there is a 0.5 volt drop across the 1k
    pot. I = E/R = 0.5/1k = 0.5 ma. Solving for the remaining two resistors is
    easy. The resistor from pot to ground = 1 / 0.5 = 2k. The resistor from + to
    the pot = 1.7/0.5 = 3.4k
  4. James W

    James W Guest

    The original poster failed to say what the 'wiper load' will be. Just
    want to make sure OP considers this
    - jim
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