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Question about car chargers

Discussion in 'Electronic Equipment' started by Ken, Jul 31, 2009.

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  1. Ken

    Ken Guest

    I have a few various car chargers that accept USB cables, attaching to
    various devices with a mini-USB connector. Each has its own output,
    from 500 mA to 1000 mAmps. I just purchased a new device (Callaway uPro
    GPS). Its car charger has an output of 500 mA.

    Can I use one of the units with higher or lower output to charge the
    battery? Is the highest charge rate determined by the battery or the
    charger? It is a PITA to always try to find the original charger
    amongst all of the gear I carry. I would prefer some options!

    Thanks
    Ken K
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  2. Ken

    Ken Guest

    Robert Baer said the following on 7/31/2009 8:57 PM:
    Thanks for the reply but I must not have been clear in my post. My
    question revolves around small electronic equipment (bluettoth speakers,
    camera batteries, GPS batteries, etc.) that can be charged in a car. I
    have a collection of 5-6 of these varying in output from 250 mA to
    1000mA and the question is whether I can use a charger of higher output
    to charge one of lower output (is there a maximum built into most
    devices to use just what is needed) or is that a dangerous process?

    Thanks
    Ken K
     
  3. Resqueline

    Resqueline

    2,848
    2
    Jul 31, 2009
    I believe you can use an as powerful USB supply as you like, the (consuming) device only uses as much as it's designed to. The USB setup is supposed to keep a regulated 5V output at all times so the current limiting has to be in the "receiving" device.
     
  4. Ken

    Ken Guest

    Robert Baer said the following on 8/2/2009 4:13 PM:
    I think I am OK, then. The latest device is a GPS which has a draw for
    recharging the battery of 500 mA. I have 750 and 1000 mA adapters which
    match the voltage, so what you are saying is that the device which
    needs 500 mA for recharging will only draw 500 mA of either the 750 or
    1000 mA chargers, as I read what you say.

    Thanks for your input (no pun intended)
    Ken K
     
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