Q Factor

Hello All


Say Impedance Z i = jwL + Rs
(Rs is in series and it is actually the internal series resistance,
this means inductor is an ideal one)


So if we assume this way, then does it mean jwL comes from the ideal
inductor? Not from any of the Rs at all?


If we want to find Q of the inductor
we will use Q= wL/Rs where SL(or jwL) is not involved totally in the Q

equation.


Am I right ?
Kindly enlighthen
Thank you


Jason

 

Hi, Jason -

That is correct.

You do not need S or j, so the relation is Q = wL/R.

John

 

Thank you John
You have been very helpful
Also I am lucky that no one sabotaged this enquiry
Cheers

Jason

 

Thank you John
You have been very helpful
Also I am lucky that no one sabotaged this enquiry
Cheers

Jason