A
Alan Combellack
- Jan 1, 1970
- 0
My apologies if these questions have been done to death but I am new to
this, and lazy
.. I know PV cells are claimed to be about 20% efficient, unless they are
very expensive. I assume this means that 20% of the incident light is
converted to electrical output. I am wondering about the relative areas of
actual collecting surface and the area blacked out by the support
structures. I hope a square metre of collecting panel area shadows only a
little more than 1 m^2. Can anyone advise me please?
The other "fact" I have seen is that PV cells now cost about $3.00 per
Watt of output power Is this calculated for a cell exposed to "full"
sunlight or to some arbitrary light level? TIA
Alan C
[email protected]
this, and lazy
.. I know PV cells are claimed to be about 20% efficient, unless they are
very expensive. I assume this means that 20% of the incident light is
converted to electrical output. I am wondering about the relative areas of
actual collecting surface and the area blacked out by the support
structures. I hope a square metre of collecting panel area shadows only a
little more than 1 m^2. Can anyone advise me please?
The other "fact" I have seen is that PV cells now cost about $3.00 per
Watt of output power Is this calculated for a cell exposed to "full"
sunlight or to some arbitrary light level? TIA
Alan C
[email protected]