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Aashish

Apr 10, 2016
6
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Apr 10, 2016
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I needed help to complete this project...the ques being stated as: Design a circuit with minimum price to solve the
-V0=(V1-V2)/3 + V3/2
 

davenn

Moderator
Sep 5, 2009
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you are going to have to give us a lot more info for anyone to help you
 

CapSteel

Mar 7, 2016
14
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Mar 7, 2016
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You might try rearranging your equation into something different:
V0 = -(1/6) (2V1 - 2V2 + 3V3).
You could build this circuit with opamps and resistors, but not sure if it meets your minimum price requirement.
 

CapSteel

Mar 7, 2016
14
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Mar 7, 2016
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Again, I'm not sure if there's a simpler way, but here goes:
See attached schematic.

-V0=(V1-V2)/3 + V3/2

Rearrange equation to get:

V0 = -(1/6)(2V1 - 2V2 + 3V3)

Opamps U1, U2, and U3 will output 2V1, 2V2, and 3V3.

Opamp U4 outputs -2V2.

Opamp U5 along with resistors R9, R10, R11, R12, and R13 are a summing amplifer which outputs the sum 2V1-2V2 +3V3.

Opamp U6 multiplies by -(1/6).

 

Aashish

Apr 10, 2016
6
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Apr 10, 2016
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6
Thanks a lot. Will seek the teachers view if this is the output he wants. Anyways you helped a lot .☺☺
 

Aashish

Apr 10, 2016
6
Joined
Apr 10, 2016
Messages
6
Need some more help for the project... The question being stated as:
Designa an analog computer circuit to solve the differential equation

d2y/dt2 + 6 dy/dt = f(t)

Where f(t) is a square wave signal.
 
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