# power consumption of integrated circuit in 0.13µm CMOS technology

Discussion in 'Electronic Basics' started by Geronimo Stempovski, May 11, 2007.

1. ### Geronimo StempovskiGuest

Hi all,

currently I am investigating a data sorting algorithm on hardware. The
algorithm was implemented in VHDL and is currently running on a Xilinx
Virtex-II Pro XC2VP70 - FF1704 FPGA. Power consumption is a crucial aspect
in the target application. Therefore I made an analysis with the Xilinx
Virtex-II Pro Web Power Tool (www.xilinx.com) and obtained satisfying
results.

Now I'd like to make an estimation what this circuit would consume on a
comparable ASIC 0.13µm CMOS technology (the FPGA is also based on a 0.13µm
CMOS technology). The target clock frequency is 180 MHz, activity ratio is
15%. Is there any rule of thumb or calculation rule?

Any help is highly appreciated !!!!

Regards Gero

2. ### Del CecchiGuest

power is .5*c*v**2*f*sf. Sounds like you know everything but C. So you
would need to synthesize or otherwise get a gate count, assume a load
per gate and go from there.

3. ### austinGuest

C * F * V^2 = P

There is no "1/2", as you get power when you charge, and also when you
discharge a node.

E=1/2 CFV^2 is appropriate for energy stored in a capacitor, not for the
power dissipated when nodes are switching (Charging AND Dis-charging).

Austin

4. ### Del CecchiGuest

true for clocks but data lines usually only transition one direction per
cycle at most. so conventionally SF=2 for clocks in power calculators.

5. ### John LarkinGuest

There are several design houses that specialize in flipping fpga
designs to asics. I bet one of them would give you a quick estimate.
Google "fpga asic conversion service" or something like that.

John

6. ### Peter AlfkeGuest

If you want to retain the 1/2, then I suggest you use T (for
transition) instead of F (for frequency), in order to avoid the
ambiguity.
A factor of 2 might actually mean something
Peter Alfke