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Pinout needed for TO-5 devices

J

John Fields

Jan 1, 1970
0
I have only one thing to say. Read the 2N4036 data that I posted to
ABSe.

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I did, a couple of times, and wondered why you didn't post the curve on
page 300 which, I'm sure, shows the power derating with elevating Tc and
Ta. Be that as it may, I'd be interested in seeing what you come up
with for a heat sink to allow the device (the transistor) to dissipate 7
watts continuously with a Ta of 25°C.
 
N

Neil Preston

Jan 1, 1970
0
From the discussion, you probably won't find a data sheet that you can rely
on for these devices.

Assuming that it is a transistor and not an IC or other device, you can use
an ohmmeter to determine the pinout. If you use a digital multimeter, use
the 'diode test' function.

Connect the positive lead to any pin and check the other pins for low
resistance or low diode drop. Rotate the lead connections until you find a
connection where one pin has a low resistance to both of the other two.
That pin is the base lead. If it is the positive ohmmeter lead, the
transistor is NPN. If negative, it is PNP. Call that pin 2.

To determine emitter and collector, do a current gain test:
If it is an NPN transistor, connect the negative lead to pin 1 and the
positive lead to pin 3. Moisten the tip of your finger and touch it between
pin 2 (base) and pin 3. If you see a drop in resistance, pin 1 is most
likely the emitter and pin 3 is most likely the collector. (The moisture
path allows some trickle of base current from the positive meter lead and
turns on the transistor.) If you are not sure, reverse the connections to
pins 1 and 3 and repeat. The connection that gives the greatest drop in
resistance will have the pos lead on the collector and the neg lead on the
emitter.

If it was found to be a PNP transistor, reverse the polarity for the above.

Good luck....
 
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