phasor to complex

[Robert Baer]

Don
I don't. I am going to try and work out what my electrochemical
cell looks like in terms of a RC network.

Wayne

Wa

If you are modeling an electrochemical cell, i can guarantee losses...

 

[Don Kelly]

Don Kelly wrote:


How do you know that the "capacitor" doesn't have some loss component? I
suspect that this is the case.

Don Kelly
[email protected]
remove the urine to answer


If that is the case then he uses Z=Vs/I which is again a measured phasor
for I- he will not be able to get away with just magnitude measurement.
Then he uses Zunknown=Z-R and there you have it. Zunknown= Ru-jXu.

He has a magnitude and a phase angle listed. I suspect that the phase angle
is that of the voltage across the "capacitor" with respect to that across
the resistor (i.e. with respect to the current.) I don't recall him any
impedance values- just the voltages.
theta1=80deg

Vs=1v
Vr=0.25v

I asked Wayne for clarification as to what is what he has adrawn two Vs
values and doesn't specify which voltage is associated with theta1. so the
problem is:
a) 1 @ 80 =0.25+jVc assuming a pure capacitor - this doesn't work as has
been pointed out.
b) 1 @ ?? =0.25 +|Vc| @80 does have a valid solution for |Vc| and for ??

Take your choice.

 

[Fred Bloggs]

He has a magnitude and a phase angle listed. I suspect that the phase angle
is that of the voltage across the "capacitor" with respect to that across
the resistor (i.e. with respect to the current.) I don't recall him any
impedance values- just the voltages.
theta1=80deg


I asked Wayne for clarification as to what is what he has adrawn two Vs
values and doesn't specify which voltage is associated with theta1. so the
problem is:
a) 1 @ 80 =0.25+jVc assuming a pure capacitor - this doesn't work as has
been pointed out.
b) 1 @ ?? =0.25 +|Vc| @80 does have a valid solution for |Vc| and for ??

Take your choice.

Right- well he does know R- so he measures magnitude and phase of Vr wrt
Vs and then I=Vr/R.