Phase shift

[Arouse1973]

The last opamp was just used to make the waveforms comparable in size so you could see them together. It is not used to calculate the phase shift. You really need to show me your calculations so I can see what you are doing. Saying please tell me what I am doing wrong isn't very helpful when I don't know what you are doing.
Thanks
Adam

 

[Ricperes]

The last opamp was just used to make the waveforms comparable in size so you could see them together. It is not used to calculate the phase shift. You really need to show me your calculations so I can see what you are doing. Saying please tell me what I am doing wrong isn't very helpful when I don't know what you are doing.
Thanks
Adam

I'm doing exactly what you said, so using R=1800 ohm and C= 3.3uF and y get phase-shift of 28.19 degrees, instead of 60º. I made this:

 

[Arouse1973]

Your calculations are correct. The formula is for a high pass type, I used a low pass. So you have to subtract 28deg from 90deg to get the answer of approx. 60deg. Or the formula is atan(2*pi*f*R*C). Sorry I should have mentioned that.
Thanks
Adam

 

[Ricperes]

Your calculations are correct. The formula is for a high pass type, I used a low pass. So you have to subtract 28deg from 90deg to get the answer of approx. 60deg. Or the formula is atan(2*pi*f*R*C). Sorry I should have mentioned that.
Thanks
Adam

No problem, I appreciate your help.So just a last question, about the The last opamp , how you dimension that?

thanks

 

[Arouse1973]

The last opamp is just a gain stage I used to make it easier to see the in an out signals together. It has non inverting gain of 1+(R3/R4).
Adam