E
Eeyore
- Jan 1, 1970
- 0
Ppppfffftttttt..... I was *always* right on this point of course !
Graham
Graham
In the above case yes, as in within a few tens of microseconds or so.
Such a method is indeed limited to situations where the frequency is known.
Graham
Fred said:Eeyore a écrit :
Obviously (hem) not.
V = a sin(wt)
V'= a w cos(wt)
V''=-a w^2 sin(wt)
w=sqrt(-V''/V)
a= V''/sqrt(-V''/V)
Right 'til nowEeyore a écrit :
Obviously (hem) not.
V = a sin(wt)
V'= a w cos(wt)
V''=-a w^2 sin(wt)
w=sqrt(-V''/V)
That one is plain stupid.a= V''/sqrt(-V''/V)
I don't check my work very carefully for newsgroup postings, since the
penalty for being wrong is zero. I'm a lot more careful when it
matters, which is how I get to sell rev A of most of my boards.
John
As regards being wrong, I and one of my design engineers are working
on the architecture of a new product. We visited the customer last
week and got an idea of his problems, and we promised him a proposal
by this coming Friday. Accordingly, we have allocated Monday, Tuesday,
and Wednesday specifically to being confused and wrong as much as we
possibly can, and we're doing mighty fine so far. I've been learning
stuff about NCOs that I never suspected, and discovered that you can
buy a might fine 16-bit DAC for $3 nowadays and that Xilinx has some
ultracool logic blocks for free.
Sometimes it pays to be wrong.
Damnation, you're right. I was assuming the frequency
was known.
Bob M.
But:Obviously (hem) not.
V = a sin(wt)
V'= a w cos(wt)
V''=-a w^2 sin(wt)
w=sqrt(-V''/V)
It will not.
John
When we say there is 110V AC, is that peak to peak?
No, that is RMS or Root Mean Square.
To calculate peak, mult RMS by 2 x (Square root of 2) (approx 1.414)
Then to get paek-to-peak, multiply peak by 2