From the wikipedia article on the PDP-8:
"In the 8/S two different logic voltages were used, an inexpensive
way to increase the fan-out of the inexpensive diode-transistor
logic."
What's that mean? Normally there are 2 logic levels. Do they mean 2
supply voltages?
I know DTL modules in the Apollo guidance computer each had
complementary outputs, so maybe that's what they're talking about.
Tom,
The Wikipedia article appears to be incorrect as far as this sentence
is concerned. The PDP-8/S is a negative logic machine using -3 and 0
volts. The DC voltages required by the logic are +10V and -15V. The
PDP-8/S Maintenance Manual at
bitsavers.trailing-edge.com/pdf/dec/pdp8/ pdp8s/PDP8S_MaintMan.pdf,
page 1-3 states: "The dc voltages required by the logic are +10V and
-15V. All logic is solid state; transistors and diodes operate on
static logic levels of 0 and -3Vdc (tolerances are 0V to -0.3V and
-3.2V to -3.9V)."
A friend experienced with PDP-8 family machines stated, "I would
hazard a guess this is just a misunderstanding of the fact that DEC
predates integrated circuits so the newer ones [PDP-8s] are plus 3 and
the power supply is +5 while the older ones are -15 power supply and
the logic is -3 volts." He also pointed out that there are R-xxx
[labeled] modules and there are S-xxx modules. The difference is
there are different resistors. The more expensive "S" cards have less
fanout but higher speed than the R-xxx modules.
He also said, "Positive stuff has only +5. The old stuff has +10 and
-15. That's not a logic level consideration. Just that some aspects
of the module need the 10 to make the spec. Plus 10 volts is even
"lower" than 0 volts when you are speaking to -3 or so as the
reference point. In any case, a designer of R-series modules can
count on a +10 voltage to help cleanup signals if need be."