R
Rich, Under the Affluence
- Jan 1, 1970
- 0
So, the boss comes into my office this morning, demanding to know the
coefficient of thermal expansion of steel. Well, I don't know the
coefficient of thermal expansion of steel off the top of my head, so
I get him to back off long enough to let me look it up, and it
turns out it's something like 6.8 ~ 8.6 ppm/deg F.
He says, "That's not gooe enough! I have to have the formula!"
I said, "That _is_ the formula. 8.6 parts per million per degree F.
I can't make it any simpler than that, except maybe translate parts
per million into thou and tenths, in which case it's not very many
at all..." And he says, "So, if it's 17.5 inches at 70 degrees, how
many inches is it at 55?"
I made him a little spreadsheet. I was tempted to make a chart,
but all he asked for was a "formula".
It came out to somehting like 17.497" or something. They're obsessing
over a hole diameter in a weldment that has no other tolerance closer
than about 1/16". (about 1.3 mm).
Thanks, just wanted to rant for a mo.
;-)
Rich
coefficient of thermal expansion of steel. Well, I don't know the
coefficient of thermal expansion of steel off the top of my head, so
I get him to back off long enough to let me look it up, and it
turns out it's something like 6.8 ~ 8.6 ppm/deg F.
He says, "That's not gooe enough! I have to have the formula!"
I said, "That _is_ the formula. 8.6 parts per million per degree F.
I can't make it any simpler than that, except maybe translate parts
per million into thou and tenths, in which case it's not very many
at all..." And he says, "So, if it's 17.5 inches at 70 degrees, how
many inches is it at 55?"
I made him a little spreadsheet. I was tempted to make a chart,
but all he asked for was a "formula".
It came out to somehting like 17.497" or something. They're obsessing
over a hole diameter in a weldment that has no other tolerance closer
than about 1/16". (about 1.3 mm).
Thanks, just wanted to rant for a mo.
;-)
Rich