Operating range of the devices

Definitely not.
For some devices this may be true, but most any electronic device is much more complex than simply a resistor.

Partly. For a resistive device your calculation is correct.
But: Min and Max ratings are not purely defined to avoid destruction from overheating due to excessive power. You'll also have to take into account several other factors like for example:

• threshold voltages of semiconductor devices (e.g. when a transistor turn on or off)
• limits to electric fields within a device (e.g. the strength of an electric field between a MOSFET's gate and channel)
• accuracy of the device (some devices work "well" for hobbyist purposes outside the defined min. and ,ax. range, but will probably fail to meet other specs when doing so)
• lifetime of the device (operating e.g. a capacitor above its rated voltage may not immediately destroy the capacitor. It will also not heat up, but the dielectric may be stressed too much so the capacitor may fail early)
• etc. etc.

Not solely. What if the device is a MOS device without bjts? No base current there. Other considerations as above also apply here.

 

Hello,

It depends on how the voltage regulators are made.
Linear voltage regulators will have a larger loss as switching regulators.
Linear regulators will hardly add noise to the system.
Switching regulators can add noise due to the switching to the system.

Looking at your example with an input range of 18 to 32 Volts with an output voltage of 24 Volts, it must be a switching regulator, likely a sepic or boost-buck regulator.
The attached PDF will show you the possible switching regulators.

Bertus

 

From the datasheets of the components and the design specifica of the regulator circuit.